If you will take a look at the String.substring(int, int) method from android. I created a small snippet to illustrate my problem.The best way to get substring in Android is using (as said) TextUtlis.substring(CharSequence, int, int) method. Like its manual says, it works like this: A null input String returns null. That's more convenient than the one provided by Java out of the box if you don't need regular expressions. Using String.substring() The easiest way is to use the built-in substring() method of the String class. Use a better overload like String.split (String regex, int limit). The easiest way is to use StringUtilssplit(, char). String wantedPart lineOfText.substring (lineOfText.indexOf (',') + 1) Since indexOf returns the index of the, itself, you need to add one to get everything past it. ![]() How to I overcome it by skipping those entry without dot(.). Find the index (position) of the first, and substring using that index. In this tutorial, we’re going to be looking at various means we can remove or replace part of a String in Java. I will get an error Exception in thread "main" : String index out of range: -1 ![]() ![]() Example of list of words to be compared: angry berry you young your apple orange yeast When user entered 'y' character, the results I am getting as text suggestion list: you young your yeast At this point, it is correct. This code is to ignore all characters after the first '' but works fine just for the first line if we read it all sequentially. If you're OK with storing it as an array/list, but not. readText userInputTextArea.getText () readTextAllInALine readText.replaceAll ('\ ', ' ') so the output after this is: Some Text Some Text again A comment A comment line Another Text Another Text againComment. To get what youre trying to do with lastSubstring(), you can efficiently use substring(). You cant efficiently find the last index with a given value using indexOf(), so lastIndexOf() is necessary. It accepts regex, so you can skip any number of spaces: String values line.split ('\\s') Then you'll have to convert these String s to the values you need: int firstNum Integer.valueOf (values 1) // anything like this. Im not aware of that sort of counterpart to substring(), but its not really necessary. String separator '-' int sepPos str.indexOf (separator) ('Substring after separator '+str.substring (sepPos. One of the options you have is to use String.split method. ![]() For that, first you need to get the index of the separator and then using the substring () method get, the substring after the separator. String str '123dance456' String substr 'dance' String parts str.split(substr) String before parts0 String after parts1 It is noteworthy that the second answer not work if we have more than one occurrence of the substring. I want to input the data into a Hashmap and do some datamapping. I was having some problem when trying to compare strings in Java. We want the substring after the first occurrence of the separator i.e.
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